# Level 38

You don't need a Bitcoin miner to proof that you can do some work.

Seal the block by finding a **nonce** that (combined with the data) will return a sha1 hash with 7 leading zeroes

```
sha1 = ( "4263dfadeb gives 193 0xfcoins to" + "943599749e" + nonce)
```

**Example:**

nonce = "132f4c5f0f"

sha1("string1"+"string2"+nonce) -> Results in sha1 hash 000000593a640078a309840d69b4e2064d09ae20 so 132f4c5f0f would be the solution if we were looking for 6 leading zeroes

Solution: